Mathematics
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OpenStudy (anonymous):
factor: x^2-6x-9y^2+9
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OpenStudy (anonymous):
\[x^2-6x-9y^2+9\]
OpenStudy (anonymous):
would grouping work here?
jimthompson5910 (jim_thompson5910):
hint: Factor x^2-6x-9y^2 and ignore the 9 at the very end
jimthompson5910 (jim_thompson5910):
btw, i think it should be x^2-6xy-9y^2+9
OpenStudy (anonymous):
i cant factor x^2-6x-9y^2 because they are two different variables
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jimthompson5910 (jim_thompson5910):
that's why I was thinking there was a typo and it should be x^2-6xy-9y^2
OpenStudy (anonymous):
nope that's not it, i copied the question right
:S
jimthompson5910 (jim_thompson5910):
oh i see what to do, one sec
jimthompson5910 (jim_thompson5910):
x^2-6x-9y^2+9
x^2-6x+9-9y^2
(x^2-6x+9)-9y^2
Do you see where to go from here?
OpenStudy (anonymous):
i dont understand why you did that
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OpenStudy (anonymous):
x^2-6x+9-9y^2
jimthompson5910 (jim_thompson5910):
factor x^2-6x+9
what do you get?
OpenStudy (anonymous):
why do we ignore the 'y' value ?
jimthompson5910 (jim_thompson5910):
just focus on this for now, you'll see later
OpenStudy (anonymous):
alright, so it would be x^2-3x-3x+9
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jimthompson5910 (jim_thompson5910):
good, keep going
OpenStudy (anonymous):
(x-3)^2
jimthompson5910 (jim_thompson5910):
so
x^2-6x-9y^2+9
x^2-6x+9-9y^2
(x^2-6x+9)-9y^2
(x-3)^2 - 9y^2
see what to do now?
OpenStudy (anonymous):
mhmm, thank you very much !
jimthompson5910 (jim_thompson5910):
that's great
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Directrix (directrix):
@burhan101
Do you recognize this expression as the difference of squares?
(x-3)^2 - 9y^2