Question

solve the equation: p(p+3)=4

Answer 1

bring the 4 over
p(p+3)-4=0

Answer 2

\[p(p+3)=4\]
\[p(p+3)-4=0\]
\[p^2+3p-4=0\]

now use the quadratic equation

Answer 3

p2 + 3p - 4 = 0?

Answer 4

of factor in your head using the factors of -4

Answer 5

so you factor out P^2+3p-4=0 @UnkleRhaukus

Answer 6

what do you get/?

Answer 7

you make the 4 a 2^2 right?

Answer 8

(p+4)(p-1) which gives you p=-4 p=1

Answer 9

@UnkleRhaukus

Answer 10

you make the -4=-1x4