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expand (2x+1)^3
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Would you like to use the Binomial Theorem here?
\[(2x+1)^3=(2x+1)(2x+1)(2x+1)\]
\[1(2x)^3(1)^0 +3(2x)^2(1)^1 + 3(2x)^1(1)^2 + 1(2x)^0(1)^3 \]
@UnkleRhaukus is right, but who'd like to multiply that much? :P
\[=(4x^2+4x+1)(2x+1)\]
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\[\implies 2x(4x^2 + 4x + 1) + 1(4x^2 + 4x + 1)\]
easy
\[(2x +1)^3\]=\[(2x)^3+(1)^3+3xy(2x+1)\]
and then solve it @shaqadry
(a+b)^3 = a^3 + 3a^2 b + 3a b^2 + b^3
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Or Use pascal Triangle to find its Coefficient
thank you everyone!
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