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Mathematics 21 Online
OpenStudy (anonymous):

expand (2x+1)^3

Parth (parthkohli):

Would you like to use the Binomial Theorem here?

OpenStudy (unklerhaukus):

\[(2x+1)^3=(2x+1)(2x+1)(2x+1)\]

Parth (parthkohli):

\[1(2x)^3(1)^0 +3(2x)^2(1)^1 + 3(2x)^1(1)^2 + 1(2x)^0(1)^3 \]

Parth (parthkohli):

@UnkleRhaukus is right, but who'd like to multiply that much? :P

OpenStudy (unklerhaukus):

\[=(4x^2+4x+1)(2x+1)\]

Parth (parthkohli):

\[\implies 2x(4x^2 + 4x + 1) + 1(4x^2 + 4x + 1)\]

OpenStudy (unklerhaukus):

easy

OpenStudy (mayankdevnani):

\[(2x +1)^3\]=\[(2x)^3+(1)^3+3xy(2x+1)\]

OpenStudy (mayankdevnani):

and then solve it @shaqadry

OpenStudy (anonymous):

(a+b)^3 = a^3 + 3a^2 b + 3a b^2 + b^3

OpenStudy (anonymous):

Or Use pascal Triangle to find its Coefficient

OpenStudy (anonymous):

thank you everyone!

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