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Mathematics 8 Online
OpenStudy (anonymous):

There are 20 people on the board of directors of a publicly listed company. Each pair of people are either friends or enemies with each other. Every person has exactly 6 enemies on the board. If every group of 3 directors form a committee, what is the total number of committees that are formed by all friends or all enemies?

OpenStudy (agent47):

Suppose you pick one guy, say director 1: So it's 20C1 = 20. Now you have to pick 2 people who are not his enemies: 20-6=14 friends, so 14C3

OpenStudy (agent47):

So a way to pick a committee consisting of all friends would be 20C1*14C3

OpenStudy (agent47):

I mean 20C1*14C2

OpenStudy (agent47):

Sorry, i typed 20C1*14C3 everywhere, but it's actually: 20C1*14C2. This is for all friends.

OpenStudy (agent47):

For all enemies, this looks like it's tricky, but I could be overthinking it. Can you check the answer or not?

OpenStudy (agent47):

aw man why did this question get closed?

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