Question

Part 1: Find the perimeter of a rectangular object which has a length √128 of feet and a width of √200 feet. (3 points)

Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. (2 points)

Part 3: What type of object in your home or school might this be? (1 point)

Answer 1

part 1 ..perimeter of rectangle = 2(length+ breadth) just put the values

Answer 2

perimeter = total length along the sides = L+W+L+W =2(L+W)

Answer 3

\[2 (\sqrt {128}+\sqrt {200})\]

Answer 4

object around you that is rectangular , like study table, A4 sheet etc

Answer 5

im still kind of lost... :/

Answer 6

\[2(\sqrt{128}+\sqrt{200})= 2(8 \sqrt 2+ 10 \sqrt 2)= 2(18 \sqrt 2)=36 \sqrt 2\]

Answer 7

@TiaW clear?

Answer 8

Part 2: you basically add all the sides of a shape to get its perimeter.
so for rectangle you both lengths and both widths to get its perimeter.
this gives the equation 2(length + breadth)
this is the shorter way of finding out the perimeter of a rectangle
the longer way is l+ l +w + w =P of rectangle
and then you just substitute the value in whatever equation you prefer.
and this is how by calculating you reach the answer, the perimeter of the rectangle.

Answer 9

Oook thanks @ghazi & @Bhagyashree

Answer 10

@ghazi in the first on u put breadth?? whats that

Answer 11

breadth= width :)

Answer 12

it is the same as width

Answer 13

Ooo thnxx

Answer 14

:)

Answer 15

Why does it not times the 2 (the radicand) as well?

Answer 16

What object do you think it is

Answer 17

it's not an object i guess, because it's something two dimensional which is hard to analyse in the form of something 3D