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can anyone help me????? xy' - 2y-x^3sinx = 0
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do i use homogenous equation or 1st order or exact?
divide through by x
move the x^2 sin(x) you'll get y' +f(x)*y = g(x)
that should be familiar:)
oh i see ! 1st order!! but are you able to use homogenous equation? is that possible?
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It's in the 'form' where you can use the 'integrating factor' method... I think I remember you referring to that as 'exact' but I'm not sure on that..
different people call it by different names, but we did it once before, iirc.
Do you know what I'm talking about?
oh i see okay! so basically try to do make it into the formula form and see if it works and use that integrating method.
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yep:)
yesthank you~~~
sure:)
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