lim as y--3 of (y^2+y-12)/(y^3-10y+3). I just can't figure out how to factor this thing, really.

Question

lim as y-->3 of (y^2+y-12)/(y^3-10y+3).  I just can't figure out how to factor this thing, really.

helder_edwin · Answer

u got
$$ \large \lim_{y\to3}\frac{y^2+y-12}{y^3-10y+3}=\frac{0}{0} $$
right?

helder_edwin · Answer

this means that the factor x-3 is present in both the numerator and the denominator

helder_edwin · Answer

u can then use synthetic division to factor them both

helder_edwin · Answer

@CaptainMathNoob ?? r u there?

anonymous · Answer

Does it explicitly say to factor, or are you familiar w/ L'Hospitals?
Can you do a synthetic division?

anonymous · Answer

Yeah I'm here, sorry.  This is a Calc 1 class and we haven't gotten to L'Hospitals yet.

anonymous · Answer

Ok, so do you know how to do a synthetic division?

anonymous · Answer

I'm vaguely familiar with it.  Guess I should go watch a youtube video, eh?

anonymous · Answer

I'll work the numerator, but yes. You should go revise that.

anonymous · Answer

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