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Mathematics 15 Online
OpenStudy (anonymous):

Given f(x) = l x l , what is the domain of f(x) = 1/8f(4x+9)-3 ?

OpenStudy (anonymous):

a) D = {x E R I x > or equal to 0} b) D = {x E R I -4 < or equal ro x < or equal to 4 c) D = {x E R } d) D = {x E R l 0< or equal to x < or equal to 9}

OpenStudy (anonymous):

@qpHalcy0n Last one :/

OpenStudy (anonymous):

I know that it has to be real numbers since it's absolute value

OpenStudy (anonymous):

\[\frac{1}{8f(4x+9) -3}\] ??

OpenStudy (anonymous):

\[\frac{ 1 }{ 8 }f (4x+9)-3\]

OpenStudy (anonymous):

Do I give any value for x?

OpenStudy (anonymous):

Oh, in that case, is there any restriction? Sure there's an absolute value, but that won't have any effect on the domain.

OpenStudy (anonymous):

It will change the RANGE.

OpenStudy (anonymous):

Oh.

OpenStudy (anonymous):

You're right.

OpenStudy (anonymous):

So a) cannot be the asnwer.

OpenStudy (anonymous):

Right, this is another linear function. The domain is all real numbers.

OpenStudy (anonymous):

It's c?

OpenStudy (anonymous):

Looks to be that way.

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