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Given f(x) = l x l , what is the domain of f(x) = 1/8f(4x+9)-3 ?
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a) D = {x E R I x > or equal to 0} b) D = {x E R I -4 < or equal ro x < or equal to 4 c) D = {x E R } d) D = {x E R l 0< or equal to x < or equal to 9}
@qpHalcy0n Last one :/
I know that it has to be real numbers since it's absolute value
\[\frac{1}{8f(4x+9) -3}\] ??
\[\frac{ 1 }{ 8 }f (4x+9)-3\]
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Do I give any value for x?
Oh, in that case, is there any restriction? Sure there's an absolute value, but that won't have any effect on the domain.
It will change the RANGE.
Oh.
You're right.
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So a) cannot be the asnwer.
Right, this is another linear function. The domain is all real numbers.
It's c?
Looks to be that way.
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