Question

2(x-3)≥5-(x+3) I need help :(

Answer 1

Start off by distributing

2(x-3)≥5-(x+3)

2x-6 ≥ 5-x-3

what's next?

Answer 2

i understand the distrubuting part, im stuck on the rest of it.

Answer 3

ok you want to isolate x

Answer 4

so you want to get all the x terms on one side and all the non x terms on the other

Answer 5

so let's move all the x terms to the left side

Answer 6

okay how do u do that?

Answer 7

Add x to both sides

Answer 8

2x-6 ≥ 5-x-3

2x-6+x ≥ 5-x-3+x

3x-6 ≥ 5-3

Answer 9

Sry it should be

3x-6 ≥ 2

Answer 10

Now add 6 to both sides

Answer 11

3x-6 ≥ 2

3x-6+6 ≥ 2+6

3x ≥ 8

Answer 12

woah Dx ugh okay i understand it from here. Thanks i suck at algebra

Answer 13

you'll get better with more practice

Answer 14

yeah it's def a lot to take in

Answer 15

i guess so lol

Answer 16

just keep at it

Answer 17

the last step is to divide both sides by 3 to completely isolate x

3x ≥ 8

3x/3 ≥ 8/3

x ≥ 8/3

Answer 18

x is finally completely isolated, so we're done

Answer 19

oh dang thats alot than i thought. I've been doing the easier ones til this problem lol. But thank you so much!

Answer 20

yw