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Find t(1) for this arithmetic sequence.
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\[d=6, S _{n}=574 , n=14\]
Sorry, for each arithmetic SERIES.
sum of n terms = (n/2)[2a + (n-1)d] where a = t(1) 574 = 7[2a + 13*6] solve for a
That makes sense, but the equation that I was given in class was: \[S{n}=\frac{ n }{ 2 } (t{1} + t{n})\] Is that the same thing? :S
tn is nth term which is a + (n-1)d - yes
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Okay, thank you so much :)
yw tn is last term
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