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State the parent function of the equation y = 1+3square root of x+2 and the transformation that were applied
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\[y = 1+3\sqrt{x+2}\]
@cwrw238 Think you could help me out? :)
@jim_thompson5910 Can you help?
Start with y = sqrt(x) Then shift 2 units to the left to get y = sqrt(x+2) Then stretch it vertically by a factor of 3 ----> y = 3*sqrt(x+2) Then shift 1 unit up ----> y = 1 + 3*sqrt(x+2)
I'm lost at the first part. :/ What's sqrt?
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sqrt(x) means \(\Large \sqrt{x}\) "square root of x"
it's short hand for writing "square root of " everytime
Haha, ok.
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