Question

Find the f '(x). f(x) = 2x^2 ; a=1
Help please!

Answer 1

if f(x) = ax^n
then f'(x) = anx^(n-1)

Answer 2

We are not allowed to use the short cut lol.

Answer 3

@Edwiener What do you mean shortcut?

Answer 4

The derivative has its long method and short method. We have to use f(x) -f(a)/ x-a

Answer 5

If so, then mention the formula:
Anyway, plug the value a = 1 in, then subtract:

Answer 6

Sorry, should have mentioned it.

Answer 7

f(x) = 2x^2

f(a) = 2a^2

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f(x) -f(a)

2x^2 -2a^2

2(x^2 - a^2)

2(x^2 - 1)

Do you see where to go from here?

Answer 8

What happened to the a on the fourth step.

Answer 9

a = 1, plug it in!

Answer 10

a = 1, so I replaced 'a' with 1

Answer 11

Okay, thanks!