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CALCULUS LIMIT: lim x->0.5- (2x-1)/|2x^3-x^2| I used direct substitution and gave me 0, but the answer says it's -4, why?
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show mw your work
(2*0.5-1) / |2*0.5^3-0.5^2| = 0
the denominator is also 0, so its 0/0 not only 0
-(2x-1)/ x^2(2x-1)=- 1/x^2 so 1/(1/2^2)= -1/(1/4) so flip the fraction and - 4
when doing calculus always reduce where you can
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do you see it the answer and why?
yes thanks guy i got it now
glad to help
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