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how do i solve e^x+9=4
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solve for x?
\[\ln4 -9=x\]
first subtract 9 from both sides, u get e^x=-5 take log on both sides, u get x ln e = ln(-5) but since ln of negative number is not defined, this equation has 'no solution'. understood this ?
@hartnn I actually think he might have meant \[e^{x+9} = 4\]
ohh!! @sirena94 is it ?
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yup, it is e^(x+9)=4 so ln4-9 is correct.
Alrighty! Thanks.
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