Question

find dy/dx for 2y^3+ xy+1=0

Answer 1

\[6y^2y \prime+y+xy \prime=0\]

Answer 2

\[xy=(x)^{'}y+(y )^{'}x\]
product rule

Answer 3

Simplest way first make x a Dependant variable, and then find dx/dy. The resprocal of it will be the answer

Answer 4

is dy/dx of 1 = 0?

Answer 5

yes dy/dx of 1 does =0

Answer 6

\[6y^2y \prime + xy \prime + y\]

Answer 7

\[y^{'}=\frac{ -y }{ 6y^2+x }\]
implicit differentiation

Answer 8

\[y ^{'}=dy/dx\]

Answer 9

thanks

Answer 10

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