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solve the following equation x^2-4x-3=0
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use sridharacharyas formula
what's that formula?
i have no idea lol
search on google
come to this site for help and you send me to another lol
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\[(4\pm \sqrt{16-12})\div2\]
it means quadratic formula: Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
@Joseph91 right
Either X=1or X=3
x is not 1
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neither 3, lol!
you can use the modes in calculator
@rodneyvs2000 use the formula i gave, u will get your roots.
thanks all
but did u get your answer as \(\huge2\pm\sqrt7\)
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