Question

Help! plz!!
Evaluate if a=2/3, b=1/6 Give your answer in form of an fraction: a+b/a-b

Answer 1

i know it's 1 but how do you get it

Answer 2

\[\frac{\frac{2}{3}+\frac{1}{6}}{\frac{2}{3}-\frac{1}{6}}\] multiply top and bottom by 6 to clear the fractions

Answer 3

\[\frac{\frac{2}{3}+\frac{1}{6}}{\frac{2}{3}-\frac{1}{6}}\times \frac{6}{6}\]
\[=\frac{4+1}{4-1}\] which is not 1

Answer 4

as a matter of fact it cannot be one, because the only way a fraction is one is if the top and bottom are the same, and \(a+b\neq a-b\)

Answer 5

that's what i thought too

Answer 6

thx