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find the value where this function is discontinous please f(x)= (2x + 1)/(x^2 + x - 2)
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Hint: Factor the denominator
(x-2)(x+1)?
wait
(x+2)(x-1)
ok what do i do next then
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What happens if you have zero in the denominator?
its discontinous?
Not just that, but we can't have zero in the denominator, can we?
no we cant
Okay, so set the denominator equal to zero and solve for x. That will tell you what values cannot equal zero and ultimately where the function would be discontinuous.
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x+2=0 x-1=0 so -2 and 1?
Bingo
oh ok i have another one similar (x-1)/(x^2 + 2x - 3) when i factor the denominator its (x+3) (x-1) so the ans are -3 and 1 right?
Looks like you've got this figured out
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