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Mathematics 14 Online
OpenStudy (anonymous):

find the value where this function is discontinous please f(x)= (2x + 1)/(x^2 + x - 2)

hero (hero):

Hint: Factor the denominator

OpenStudy (anonymous):

(x-2)(x+1)?

hero (hero):

wait

hero (hero):

(x+2)(x-1)

OpenStudy (anonymous):

ok what do i do next then

hero (hero):

What happens if you have zero in the denominator?

OpenStudy (anonymous):

its discontinous?

hero (hero):

Not just that, but we can't have zero in the denominator, can we?

OpenStudy (anonymous):

no we cant

hero (hero):

Okay, so set the denominator equal to zero and solve for x. That will tell you what values cannot equal zero and ultimately where the function would be discontinuous.

OpenStudy (anonymous):

x+2=0 x-1=0 so -2 and 1?

hero (hero):

Bingo

OpenStudy (anonymous):

oh ok i have another one similar (x-1)/(x^2 + 2x - 3) when i factor the denominator its (x+3) (x-1) so the ans are -3 and 1 right?

hero (hero):

Looks like you've got this figured out

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