Question

How do you graph y=cot(x+π/4)?

Answer 1

You would shift the entire graph of y=cot(x+π/4) to the left by π/4

Answer 2

so the new asymptotes are at -9π/4, -3π/4, -π/4, π/4 and 3π/4 and so on depending on your domain

Answer 3

i got the period=π and phase shift=-π/4 as how my book says to do
and the one complete period is (π/4, 5π/4) i just don't know how the graph is supposed to look like

Answer 4

Here is a graph: http://i.minus.com/iRECCZgnomJep.gif

Answer 5

@jeremyb that's how i graphed mine, thank you