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3/2 x ≤ -1/4 =
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What I have is x ≤ -6
Is the question \(\frac{3}{2}x \le -\frac{1}{4}\) ?
yes
Divide both sides by 3/2, what do you get?
what I got is x > 0
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That doesn't look right :( \(\frac{3}{2}x \le -\frac{1}{4}\) \[\frac{\frac{3}{2}x}{\frac{3}{2}} \le -\frac{\frac{1}{4}}{\frac{3}{2}}\]\[x \le -\frac{2}{3}\times \frac{1}{4}\]Simplify the right side.
3/12
Nope.. cancel the common factor first, then multiply the fractions together.
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