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4/(a+3)+2/3a
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\[a=-\frac{ 3 }{ 7 }\]
did i win the best response =)
are you there
Thats not one of the answers
what did you need to know that is the root to A
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to add them
o then =0
4(3a)+2(3+a) /(3a^2+9a)
0 is the answer then
a.12a+2/3a(a+3) b.14a +6/a+3 c.12a+2/3a d.14a+6/3a(a+3)
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d
Is this (4/(a+3)+2/3a) supposed to be: [ 4/(a+3)] + (2/3) a ] As stated, it is difficult to tell which terms go in the numerator and which in the denominator.
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