Question

Solve the equation by factoring I ( quadratics)
3x^2+3x=18
I got x=-2, x=3
Is that correct?

Answer 1

First get the 18 on the same side as the x's.

Answer 2

start by subracting 18 from both sides to get 3x`2+3x -18=0

Answer 3

You're almost right, but you have to watch your signs.

Answer 4

I got 3x^2+3x-18=0
(3x+6)(x-3)
3x+6=0
3x=-6
x=-2

x-3=0
x=3

Answer 5

That is incorrect, because you would get -3x....you want a +3x

Answer 6

You can, however, factor a 3.
3(x^2 + x - 6)

That factors very nicely.

Answer 7

Let me try it that way

Answer 8

i got the same answer

Answer 9

Ok, how does x^2 + x - 6 factor?

Answer 10

I think I am factoring incorrectly
(x+2)(x-3)

Answer 11

You are. FOIL that out and see what you get. To get a POSITIVE x, the LARGER constant must remain with the (+) sign.

Answer 12

The factors are (x-2)(x+3)

Answer 13

x=2 amd x=-3 ?

Answer 14

Correct, THOSE are the zeroes/roots of the function.

Answer 15

Thank you

Answer 16

Np