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Mathematics 12 Online
OpenStudy (anonymous):

Factor -3x^2 - 4x + 15 Please explain!

OpenStudy (lgbasallote):

you can break down the middle term into \[-(3x^2 + 4x - 15) \implies -(3x^2 - 5x + 9x - 15)\] does that help?

OpenStudy (anonymous):

Not at all, I'm sorry! This is the one thing I can never figure out

OpenStudy (lgbasallote):

but...you get how -3x^2 - 4x + 15 became -(3x^2 + 4x - 15)?

OpenStudy (anonymous):

Hmm, I think so yeah

OpenStudy (lgbasallote):

what about when i turned it into -(3x^2 - 5x + 9x - 15)...did you get that?

OpenStudy (anonymous):

Nope

OpenStudy (lgbasallote):

well...do you agree that 9x - 5x = 4x?

OpenStudy (anonymous):

Mhm!

OpenStudy (lgbasallote):

so do you get how -(3x^2 + 4x - 15) became -(3x^2 - 5x + 9x - 15)?

OpenStudy (anonymous):

Why would you use those two numbers instead of anything else?

OpenStudy (lgbasallote):

good question

OpenStudy (lgbasallote):

because of this next step im about to do

OpenStudy (anonymous):

Oh okay! Continue c:

OpenStudy (lgbasallote):

\[-(3x^2 - 5x + 9x - 15) \implies -(x(3x - 5) + 3(3x - 5))\] do you get what happened there?

OpenStudy (anonymous):

Yup!

OpenStudy (lgbasallote):

wonderful. now do you see that 3x - 5 is common above? that means i can factor it out \[\implies -(3x - 5)(x+3)\]

OpenStudy (lgbasallote):

do you get what happened there?

OpenStudy (anonymous):

Oh, yes! Thank you (:

OpenStudy (lgbasallote):

welcome

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