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Find the slope m = y^2-y^1 --------- x^2- x^1 of a line passing through the given points. (3,3) and (4,0)
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is that the formula for the slope? :s
Substitute the values for x and y: \[\frac{ 0 - 3 }{ 4 - 3 }\]
so i just solve that :)
Yes
slope of a line passing through the given points : \((x_1,y_1)\) and \((x_2,y_2)\) \[\frac{y_2-y_1}{x_2-x_1}\]
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-3 is what i got :)
That helps explain the values of the formula very well^
Nice work(:
Thanks everyone :)
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