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in laplace transform unit step function is 1/s it is more complicated than 1. please help me
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This makes no sense.
\[\mathcal{U}(t-a)\stackrel{\mathcal{L}}{\longrightarrow}\frac{e^{-as}}{s}.\]Is this what you're referring to?
a function is attached with e^-st and integrate zero to infinity , we can use any letter insted of s what is the significance of s
the Laplace transform of unit step \( \theta(t-0) \) is 1so ??
s is just a variable.....
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*1/s
try this \[ \int_0^{\infty} \theta(t) e^{-st} dt\] this is same as Laplace transform of unit value because laplace transform naturally chops off any information that is before the time t=0.
the step function \( \theta(t-0)\) naturally chops off into that is at <t=0 ... so it would be same.
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