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Physics 12 Online
OpenStudy (anonymous):

http://gyazo.com/43e1a333db393b99b16c6363e543c3ef

OpenStudy (anonymous):

I can't understand if they mean vectorially or not, as A could mean\[|\mathbf{T_L+T_R}|=|\mathbf{W}|\]

OpenStudy (anonymous):

Well, 1 Bold letters are vectors 2 The horizontal projections of T_R and T_:L must balance to 0 - nothing elese will balance them. Now - which of those two has a larger cos(angle) with the horizontal ? That tension must be smaller because it balances a more-reduces "opponent". Think of it @henpen - and light will reveal itself upon you

OpenStudy (anonymous):

My final guidabce here - which cosine is larger - that T must be smaller. More than that will spoyl you

OpenStudy (anonymous):

Thanks- I understand. Is my intuition correct?|dw:1347901828108:dw| And as b_x=a_x, the y components must be f(y). The problem I was having is that the tension is parallel to the string. That was stupid of me!

OpenStudy (anonymous):

I mean, I even KNEW the answer (physically), but my erroneous mathematics misguided me.

OpenStudy (anonymous):

focus on the guide above

OpenStudy (anonymous):

I understand your guide.

OpenStudy (anonymous):

legi , numero, vici

OpenStudy (anonymous):

vinci, surely?

OpenStudy (anonymous):

vici , meus discipulus, vici !

OpenStudy (anonymous):

nonne?

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