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dv= 8x^2dx, what is v=dx? Please help
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Don't really understand this, let's integrate so v = 8x^3/3 + C Does that help?
if i may ask how would you know..i dont know how i would get 8x^2dx
"i dont know how i would get 8x^2dx" ???? You gave this in the question.....
yes but im asking how would you derivrate 8/3 x^3 to 8x^2?
Ah, OK..... v = 8x^3/3 + C so dv/dx = 3* 8x^(3-1) / 3
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In general, ax^n dx = n*a * x^(n-1)
oh ok i see thanks so much!!
ur welcome
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