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I need help with the following angles question...
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I think number 7 is 90?
right
because \[\overline{PQ} \perp \overline{QR}\] so it's 90
what about #8 any ideas?
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i know that i have to somehow add all three of the given measurements together.
right. you're close. you need to do that to find x
according to angle sum theorem \[\angle PQR = \angle PQT + \angle TQS + \angle SQR\] so... \[90 = 2x - 5 + 4x + 5 + 3x\] do you get what happened?
Yeah
good. so now solve for x
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10?
right
now. \[\angle TQR = \angle TQS + \angle SQR\] so... \[\angle TQR = 4x + 5 + 3x\] substitute 10 for x here then simplify
75?
right
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can you do the third one now?
or do you still need help?
I'm ok thanks :)
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