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Mathematics 10 Online
OpenStudy (anonymous):

How I figure out an equation for a function?

OpenStudy (anonymous):

This is the function,

OpenStudy (anonymous):

looks like a hyperbola shunted over and down

OpenStudy (anonymous):

What do you mean by that?

OpenStudy (anonymous):

Well a hyperbola is 1/x, centred on (0,0) right?

OpenStudy (anonymous):

I have no idea. I've never had a problem like this

OpenStudy (anonymous):

So then you shift it down 3 and 5 across,that would be y+3= 1/(x - 5) Do you have some points we can test?

OpenStudy (anonymous):

It said that the graph was a translation of y = 2 / x, is that what you are referring to?

OpenStudy (anonymous):

Oh well I wasn't far out...:-)

OpenStudy (anonymous):

It is not a hyperbola

OpenStudy (anonymous):

hyperbolas only open down and up or left and right.

OpenStudy (anonymous):

That's parabolas

OpenStudy (anonymous):

y=2/x is a hyperbola

OpenStudy (anonymous):

I don't think you are right. Hyberbolas have asymptotes that lie on the +/-x=+/-y lines

OpenStudy (anonymous):

I was just using my ti 84 calc, I tried the equation ' y=2/(x-3) -5 & it seems to work? But I really cant tell

OpenStudy (anonymous):

i guess if you rotate this graph 45 deg then you're correct

OpenStudy (anonymous):

I mean I entered it & the same image that I posted above came up, but I'm not sure if thats what the question was wanting

OpenStudy (anonymous):

It's not a rotation, it is a translation

OpenStudy (anonymous):

Ok, back to the problem at hand.....

OpenStudy (anonymous):

We know it is a translation so it has the form y+a =2/(x-b) and we can use some of the datapoints to work out what is a and b

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