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The figure shows a triangular wooden frame ABC. The side AD of the frame has rotted and needs to be replaced. What is the length of the wood that is needed to replace AD?
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@ganeshie8 ?
find tan 30= db /14 get value of db then find tan (45)= ab /14
after finding ab, see that ab=ad+db, subtract value of db to find ad
does that help
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@dorothynichole Look at the outer triangle. It is a 45-45-90 triangle and the 45-45-90 theorem applies. Segment AB = 14. Now look at Triangle DBC. It is a 30-60-90 triangle and that theorem applies. The 60 degree leg BC is 14. Therefore, DB has length 14/(square root of 3). The rotten section AD is equal to AB - DB = 14 - 14/(square root of 3) = 5.917 units (approx)
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