Question

Find three consecutive odd integers that when the 1st is added to twice the second and three time the 3rd, the result is 58

Answer 1

I'm not from us, odd is divisible by two or not divisible by 2?

Answer 2

@ganeshie8

Answer 3

Let x be the first odd number then the other two consecutive odd integers will be (x+2) and
(x+4)

Answer 4

Now,
x+2(x+2) + 3(x+4)=58

Answer 5

SOLVE FOR X

Answer 6

can u?

Answer 7

yes thank you.

Answer 8

WELCOME

Answer 9

is the first x+2 supppsed to be 2x?

Answer 10

Nope...... its x+2

Answer 11

how do I solve then?

Answer 12

x+2(x+2) + 3(x+4)=58
x+2x+4+3x+12=58
6x+16=58
6x=42
x=7

Answer 13

7, 9, 11

Answer 14

YEP

Answer 15

thank you

Answer 16

welcome