how to find the quadratic equation that has the vertex (-2,5) and whose graph passes through the point (0,9)
\[f(x)=a(x-h)^{2}+k\] you know this formula right?
haha nope slept through it... haha yea...
read you class notes!! but plug in your vertex so you get \[f(x)=a(x+2)^{2}+5\] so far so good?
haha dude he talk most the time and his notes are all over the place, and how i take notes while sleeping??
oh and i had a game on that day too XD sooooo yea..
but still did you understand?
yea i get the vertex but how you know if it pass through the lines that was given??
then yu plug in the point. \[9=a(0+2)^{2}+5\]
oh okay. then you solve??? but solve for what?
solve for a
okay i got one and what you do with the answer??
plug in yur a,h, and k values.
ummmmm what??? it'll just be the same rifht?? f(x)=(x+2)^3+5?
*right need my auto correct haha
nope. its not a 3. its a 2 but yeah thats pretty much it.
sorry that was bad typing skills...
haha noticed.
im doing chem while doing math... so yea... and my mom watching corny asian drama and the flirting hella stupid...
haha how nice... did yu understand the answer tho?
haha okay, and yes i got it. haha im super sleepy... need to finish homework... haha you start on chem dont forget
haha finish yurs. ima start in the morning.
haha yea i gotta catch up on apush im still on chap 8 TT.TT sad...
haha then? why yu here? haha finish! haha jkjk
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