Question

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Answer 1

can u find the slope of the line in your graph?

Answer 2

the intercepts are (-8,0) and (0,-4) so the slope is
\[ \large m=\frac{0+4}{-8-0}=\frac{4}{-8}=-\frac{1}{2} \]

Answer 3

so the line in the graph is
\[ \large y-0=-\frac{1}{2}(x+8) \]

Answer 4

which can be rewritten as
\[ \large 2y=-x-8 \]
or
\[ \large x+2y=-8 \]

Answer 5

do u see the origin (0,0) is in the shaded area?

Answer 6

if we replace (x,y)=(0,0) then we have
\[ \large 0+2\cdot0=0>-8 \]

Answer 7

then the shaded area is
\[ \large x+2y>-8 \]
or
\[ \large 2x+4y>-16 \]
(after multiplying by 2, the last inequality)

Answer 8

it looks like that (u have a typo).

Answer 9

D has no sign > or <

Answer 10

then, it is D

Answer 11

no sign > or < or >= or <=

Answer 12

\[ \large y?2x+6 \]

Answer 13

<= solid line

Answer 14

\[ \large y\leq2x+6 \]
\[ \large -2x+y\leq6 \]
if (x,y)=(0,0) then
\[ \large -2\cdot0+0\leq6 \]
is true

Answer 15

D

Answer 16

gotta go. bye. good luck