Please help!!!!!!!
Sam counted the lines of a page in his book. Counting by threes gave a remainder of 2, counting by fives also gave a remainder of 2, and counting by sevens gave a remainder of 5. How many lines were on the page?
Show work.
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OpenStudy (anonymous):
I think this needs modular arthemetic. So @mukushla could help
OpenStudy (anonymous):
x MOD 3=2
x MOD 5=2
x MOD 7=5
OpenStudy (anonymous):
What's mod?
OpenStudy (anonymous):
@mukushla u busy?
OpenStudy (anonymous):
yeah we can use mods but lets think easier
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OpenStudy (anonymous):
let the number of pages be n
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Counting by threes gave a remainder of 2 so n=3k+2
OpenStudy (anonymous):
CRT have fun
OpenStudy (anonymous):
counting by fives also gave a remainder of 2 so n=5j+2
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hartnn (hartnn):
tried that 4 unknowns.,3 equations....
OpenStudy (anonymous):
what am i doin???
OpenStudy (anonymous):
Ya. agreed with @hartnn
OpenStudy (anonymous):
@satellite73 come here plz :)
OpenStudy (anonymous):
Anyone found the answer?
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OpenStudy (anonymous):
I think there are infinite number of answer
OpenStudy (anonymous):
What's one of them?
OpenStudy (anonymous):
47
OpenStudy (anonymous):
I have figured it out that the last digit must be 7
OpenStudy (anonymous):
i think they mean to find minimum number of pages and so going with trial and error
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hartnn (hartnn):
agreed, minimum and trial and error.
OpenStudy (anonymous):
I think they are looking for the number of lines in one page.
OpenStudy (anonymous):
257
OpenStudy (anonymous):
Explain
OpenStudy (anonymous):
The last digit must be 7
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