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Physics 16 Online
OpenStudy (anonymous):

Can somebody help me derive this?

OpenStudy (anonymous):

OpenStudy (anonymous):

Basically my professor wants me to prove the first equation by manipulating the 2nd one, but I don't understand how to do this

OpenStudy (anonymous):

T in kelvins?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

for the second equation it is Kelvin. for the first it is celsius

OpenStudy (anonymous):

find the value of the expression at T=273 deg

OpenStudy (anonymous):

that will be the constant term (331)

OpenStudy (anonymous):

which expression?

OpenStudy (anonymous):

the one you were given as a starting point from which to derive a linear approximation \[\sqrt{ \frac{\gamma RT }{ M }}\]

OpenStudy (anonymous):

ok so 273 degrees because it is kelvin

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so i need to know gamma, molar mass and R of air to do this?

OpenStudy (anonymous):

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