a football is thrown into the air. the height, h(t), in metres, after t seconds is modelled by h(t) = -4.9(t-1.25)^2 + 9. how high off the ground was the ball when it was thrown? please explain!
The height it was thrown from is going to correspond to the y intercept.
If you logically think about it, at what time is the ball going to be thrown at?
i suck at math omg idk
Don't get frustrated, just think. The ball is going to be released at t=0, the time doesnt start until the ball is released.
so do i have to replace the t with something?
Good, you're starting to think on the right track. What do you think you need to replace t with?
if i replace it with 0 will that make sense..
It makes sense to me ;) does it makes sense to you?
ya so is that the right answer :)
That is not your answer yet, when you input a t (time sec) into this function, what will it output?
doesnt it already have a t..
Yes, but when you input a t value, say t=0, what will the function output?
the time it was thrown?
When you input t=0 into the function, it will output the corresponding height. h(0) = -4.9(0-1.25)^2 + 9
ohhhhhhhh
So how high will the ball be at t=0 seconds?
do i just solve for h?
Yes, well, h is already isolated, so just solve the right side of h(t) = -4.9(t-1.25)^2 + 9
and substitute 0 in for t
OMG thank you! you saved my life! i have a test tomorrow and i was struggggling with that question
Feel free to give out a "best response" and leave a testimonial. :) What did you get for the height at t=0?
1.34 and i willl !
Right on! are you allowed to use a graphing calculator, if so, I can show you a trick!
yess we are
Do you use a ti 83 or 84?
no idk how
okay, maybe we will leave that for another time! :) good luck on the test!
lol thats okay this is easy enough! thanks again! you're awesome :)
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