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OpenStudy (anonymous):
Solve each quadratic equation using factoring??
Pleasee help :)
2x^2+12=11x
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OpenStudy (cgreenwade2000):
Not even a quadratic equation
OpenStudy (theviper):
is it 2x^2+12=11x
OpenStudy (anonymous):
yeah my bad
OpenStudy (anonymous):
i fixed it
OpenStudy (cgreenwade2000):
Set the equation so you get
ax^2+bx+c = 0
That's step one.
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OpenStudy (anonymous):
firs get everything on one side: 9x-12=0
then you can factor our a 3: so 3(3x-4)=0
divide 3 and add 4: 3x=4
x=3/4
OpenStudy (cgreenwade2000):
James, that's the wrong equation.
OpenStudy (anonymous):
@cgreenwade2000 noo its not he already simplified it
OpenStudy (theviper):
2x^2+12=11x
2x^2-11x+12=0
2x^2-8x-3x+12=0
2x(x-4)-3(x-4)=0
(2x-3)(x-4)=0
OpenStudy (anonymous):
thanks @TheViper your awesome :))) look out for my next ones
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OpenStudy (cgreenwade2000):
Viper, she needs to understand how to do the problem.
OpenStudy (anonymous):
@cgreenwade2000 i do understand how to do it
OpenStudy (cgreenwade2000):
So you can factor the equation x^2+2x+1=0
OpenStudy (anonymous):
yeah i'm just too lazy to do it i'm in a rush i have other homework to do i just dont wanna sit here for hours doing a math problem
OpenStudy (cgreenwade2000):
It's good practice. And x^2+2x+1=0 is really easy to factor.
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