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Pre Calc: 29. For what value of k will the graph of 2x + ky = 6 be perpendicular to the graph of 6x – 4y = 12?
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recall that perpendicular implies that the slope M of the two lines you are comparing are "opposite reciprocals"
So, start by getting the lines into the form y=mx+b y=-2x/k +6/k y=6x/4+12/-4 6/4=3/2 so the opposite reciprocal of this slope is -2/3
k = 3.... Product of slopes should be -1(the lines are to be perpendicular) and slope of 6x-4y =12 is 3/2 and slope of perpendicular line is -2/3 which is possible iff k(coefficient of x) is 3....
Thank you <3 <3
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