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Mathematics 10 Online
OpenStudy (saifoo.khan):

Please give a short explanation too.

OpenStudy (saifoo.khan):

OpenStudy (anonymous):

a. because if we put x= -6 the function approaches infinity

hartnn (hartnn):

divide x in numerator and denominator. then because x->infinity, 12/x->0 so u are left with 3/2 only

OpenStudy (saifoo.khan):

So in short we have to the function undefined?

OpenStudy (anonymous):

ya right i guess m wrong :p

OpenStudy (saifoo.khan):

Sorry, don't get you.. @hartnn

hartnn (hartnn):

dividing x in numerator and denominator , we get (3+12/x)/(2-12/x) agreed ?

OpenStudy (saifoo.khan):

Yes.

hartnn (hartnn):

now when X gets infinitely larger 12/x and -12/x gets infinitely smaller. agreed ?

OpenStudy (saifoo.khan):

I think, yes..

OpenStudy (anonymous):

opposite

hartnn (hartnn):

so to find what f(x) approaches, we put 12/x =0 and -12/x =0 then we get only 3/2. ok ?

OpenStudy (saifoo.khan):

Nope. Don't get this step.

hartnn (hartnn):

\[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }\] because X is very large 1/X is very small and can be taken as 0.

OpenStudy (saifoo.khan):

i see.. thanks.

hartnn (hartnn):

welcome :)

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