Please give a short explanation too.
a. because if we put x= -6 the function approaches infinity
divide x in numerator and denominator. then because x->infinity, 12/x->0 so u are left with 3/2 only
So in short we have to the function undefined?
ya right i guess m wrong :p
Sorry, don't get you.. @hartnn
dividing x in numerator and denominator , we get (3+12/x)/(2-12/x) agreed ?
Yes.
now when X gets infinitely larger 12/x and -12/x gets infinitely smaller. agreed ?
I think, yes..
opposite
so to find what f(x) approaches, we put 12/x =0 and -12/x =0 then we get only 3/2. ok ?
Nope. Don't get this step.
\[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }\] because X is very large 1/X is very small and can be taken as 0.
i see.. thanks.
welcome :)
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