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OpenStudy (saifoo.khan):
OpenStudy (anonymous):
a.
because if we put x= -6 the function approaches infinity
hartnn (hartnn):
divide x in numerator and denominator.
then because x->infinity, 12/x->0
so u are left with 3/2 only
OpenStudy (saifoo.khan):
So in short we have to the function undefined?
OpenStudy (anonymous):
ya right
i guess m wrong :p
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OpenStudy (saifoo.khan):
Sorry, don't get you.. @hartnn
hartnn (hartnn):
dividing x in numerator and denominator , we get (3+12/x)/(2-12/x)
agreed ?
OpenStudy (saifoo.khan):
Yes.
hartnn (hartnn):
now when X gets infinitely larger 12/x and -12/x gets infinitely smaller.
agreed ?
OpenStudy (saifoo.khan):
I think, yes..
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OpenStudy (anonymous):
opposite
hartnn (hartnn):
so to find what f(x) approaches, we put 12/x =0 and -12/x =0
then we get only 3/2.
ok ?
OpenStudy (saifoo.khan):
Nope. Don't get this step.
hartnn (hartnn):
\[\lim_{x \rightarrow \infty}\frac{ 3+12/x }{ 2-12/x }=\frac{ 3+0 }{ 2-0 }=\frac{ 3 }{ 2 }\]
because X is very large 1/X is very small and can be taken as 0.
OpenStudy (saifoo.khan):
i see.. thanks.
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