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If the sum of a certain number of terms of the AP 25,22,19,... is 116.Find the last term.
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Good Day Joyal, the arithmetic pogression has a formula that you may be able to use:\[a_{n} = a_{m} + (n-m)(d)\] \[s = \frac{ n }{ 2 } (a _{1} + a _{n})\] now for you to be able to solve the problem you should fist understand which on the given you will be using to substitute on the formula
on the given formula: n = no. of terms a sub m = any term before a sub n a sub n = last term m = position of a sub m in the progression. d = gap between the progressing numbers Now begin to substitute using my formula, good luck. I hope this helps.
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