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In a given quadrilateral, AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD. Show that.........
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\[\angle A\quad >\quad \angle C\quad and\quad \angle B\quad >\quad \angle C.\]
^^FIG..
@sauravshakya @saifoo.khan @amistre64
help
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Thanks for comin' n helping !!
|dw:1348061247843:dw|
I have brought the fig..
Can we do construction?
@Rohangrr can we?
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KK
Ok.... draw a line from A parallel to BC....... Now this line must meet CD as CD>AB So,|dw:1348061853227:dw|
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