Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Simplify the given expression; Add and subtract rational expressions. (1/4x^2) + (6/2x+5)

OpenStudy (anonymous):

|dw:1348064143943:dw|

OpenStudy (anonymous):

you should start by unpacking the first set of terms with the exponent in it. can you factor that out using just a standard factoring method?

OpenStudy (anonymous):

thats what i dont understand how to do.

OpenStudy (anonymous):

\[\frac{ 1 }{ (2x-5) (2x+5) } + \frac{ 2 }{ 2x+5 }\]

OpenStudy (anonymous):

to factor, 4x^2 -25.. you need to figure out what terms you can multiply the C, or constant terms by in order to end up with the middle term.. which in this case isnt there. so its 0... so it has to be something that multiplies to -25 and adds up to 0 for the middle term

OpenStudy (anonymous):

do you understand how to foil?

OpenStudy (anonymous):

\[4x ^{2} - 25\] is like \[4x ^{2} + 0x - 25\] to make it easier to understand

OpenStudy (anonymous):

so now you can see the three terms.

OpenStudy (anonymous):

so you know x(x) is x^2 and u know that 2x(2x) is 4x2.. so that can go (2x )(2x )

OpenStudy (anonymous):

now look at the term -25.. what can u multiply to make negative 25 that also equals 0 when you add them up?

OpenStudy (anonymous):

now that we have factored the term.. you should multiply the numerators and denominators by the least common denominator. do you understand how to do that?

OpenStudy (anonymous):

yes i do.

OpenStudy (anonymous):

ok you got it from here then?

OpenStudy (anonymous):

a tip.. you can use the quadratic formula to find out the roots for factoring as well. the ti 83 graphing calc can be programmed for it.. and will save you a lot of time checking your work.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!