eliminate the parameter t. find a rectangular equation for the plane cure defined by the parametric equations.
x = 6 cos t
y = 6 sin t
0

Question

eliminate the parameter t. find a rectangular equation for the plane cure defined by the parametric equations. 
x = 6 cos t
y = 6 sin t
0<= t <=2n

anonymous · Answer

do you know what 
$$(\cos(t), sin(t))$$ looks like?

anonymous · Answer

yeah

anonymous · Answer

they are points on the unit circle
you have points on the circle with radius 6

anonymous · Answer

okay I just didn't know if it would be x^2 - y^2 = 6 or x^2 + y^2 = 6

anonymous · Answer

it is neither

anonymous · Answer

oh so you have to square the 6 which would be 36 right

anonymous · Answer

yes

anonymous · Answer

so then would it be add or subtract

anonymous · Answer

if  you square and add you get 
$$x^2+y^2=36\cos^2(t)+36\sin^2(t)=36(\cos^2(t)+\sin^2(t))=36$$

so it is $x^2+y^2=36$

anonymous · Answer

thank you