Question

HELP!
1) A right triangle has one leg of length 8 and another leg of length 9. What is the length of the hypotenuse of the triangle?

2)A right triangle has a hypotenuse of length 15 and a leg of 9. what is the length of the other leg of the triangle?

Answer 1

try this equation:
a^2+b^2=c^2

Answer 2

8^2+9^2=c^2
15^2+9^2=c62

Answer 3

OK AND THEN?

Answer 4

225+81= c^2?

Answer 5

the you square it.

Answer 6

how???

Answer 7

using square root, you basicly get rid of the squared "c". i,e it would be 15+9=c

Answer 8

wait but the hypotenuse is 15 isnt that suppose to be C?

Answer 9

the the hypotenuse is 15+9 not 15

Answer 10

thats problem #2 also

Answer 11

wait i am confused lol ok you use the equation
a^2+b^2=c^2 right? like the hypotenuse is a^2? not c^2?

Answer 12

no, the hypotenuse is a^2_b^2, but you took away the squares remember? so then it would be 15+9=c

Answer 13

okkkk and then? i just add it?

Answer 14

yea, the answe rfor #2 would be 15+9=c

Answer 15

nopes, it won't be c=15+9.

Answer 16

yes it would hartnn

Answer 17

omg.........what??? i am so confused now lol

Answer 18

for 1st problem:
hypotenuse = c
\(a^2+b^2=c^2 \\ 8^2+9^2=c^2=145 \\ c=\sqrt{145}=12.04\)

Answer 19

i got that one!!! :D but how do i solve the other one?

Answer 20

dont i have to do the same thing?

Answer 21

okay, hartnn, you just confused me, and im in algebre 3. what the hell did you just do??

Answer 22

for 2nd problem:
hypotenuse c = 15 .
\(a^2+b^2=c^2 \\ 9^2+b^2=15^2 \\ b^2=15^2-9^2 \\ b^2=225-81=144 \\b=\sqrt{144} \\b=12\)

Answer 23

@andriod09 which step u are confused with ?

Answer 24

@ayojenn got the 2nd one ?

Answer 25

everything! 1st, i cant see equations used with the equation button, so thats one, and 2, thats not how i was taught to to pythagorium theory.

Answer 26

yesss that what i was trying to tell @andriod09 , i knew the hypotenuse was c^2

Answer 27

ik that, thats what i was getting to,

ill be right back.

Answer 28

the hypotenuse = c and not c^2

Answer 29

wait what???? where did you get 82?

Answer 30

for 2nd problem:
hypotenuse c = 15 .
a2+b2=c2
9^2+b^2=15^2
b2=15^2−9^2
b2=225−81=144b=144
b=12

i never got 82

Answer 31

hartnn Best Response 0
ohh....wait
1st problem:
a2+b2=c2
82+92=c2=145 <--- 82
c=√145=12.04

Answer 32

ohh....wait
1st problem:
a^2+b^2=c^2
8^2+9^2=c^2=145
c=√145=12.04

Answer 33

i meant that^
sorry for confusion.....

Answer 34

yes thats what i got :D
lol its okk

Answer 35

ok theres another problem but i solved it just let me know if its correct ok?

Answer 36

okay :)

Answer 37

A right triangles has a hypotenuse of length 21 and a leg of length 14. What is the length of the other leg of the triangle

Answer 38

this is what i got...

Answer 39

14^2+v^2=21^2
b=21^2-14^2
441-196
square root 245=
15.65?

Answer 40

absolutely correct! :)
u are good at this :D

Answer 41

omg yay i learned!!! haha thank you :D

Answer 42

welcome :)