HELP!
what is the area of the triangle shown below?
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OpenStudy (anonymous):
|dw:1348070284794:dw|
hartnn (hartnn):
can u calculate the other leg using pythagoras theorem, just as we did in last problem ?
hartnn (hartnn):
then area will be 0.5(product of 2 legs).
OpenStudy (anonymous):
thats how i do it??
OpenStudy (anonymous):
wait wait let me do it
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OpenStudy (anonymous):
168??
hartnn (hartnn):
168 what? other leg or area?
OpenStudy (anonymous):
area? lol
OpenStudy (anonymous):
i did this.... 21x16=336 (1/2) = 168?
hartnn (hartnn):
no!
see my first comment.
can u calculate the other leg using pythagoras theorem, just as we did in last problem ?
first calculate the other leg.........
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OpenStudy (anonymous):
im confused :( lol so i have to do
a^2+b^2=c^2?
hartnn (hartnn):
yes! because its a right triangle....
OpenStudy (anonymous):
ok so its gonna be 16^+21^2=c^?
OpenStudy (anonymous):
no wait its 1
hartnn (hartnn):
no.... c is the hypotenuse = 21
\(16^2+b^2=21^2\)
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OpenStudy (anonymous):
16^2+b^2=21^2 right?
OpenStudy (anonymous):
yes yes lol got it, wait let me try to solve it lol
OpenStudy (anonymous):
13.60!!
OpenStudy (anonymous):
so no i multiply that with 16 right?
OpenStudy (anonymous):
*now
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OpenStudy (anonymous):
then by 0.5
hartnn (hartnn):
yes, thats other leg, now area = 0.5 * 16 * 13.6
hartnn (hartnn):
yup
OpenStudy (anonymous):
is it 108.8?
hartnn (hartnn):
yup, u got it :)
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