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Mathematics 15 Online
OpenStudy (anonymous):

HELP! what is the area of the triangle shown below?

OpenStudy (anonymous):

|dw:1348070284794:dw|

hartnn (hartnn):

can u calculate the other leg using pythagoras theorem, just as we did in last problem ?

hartnn (hartnn):

then area will be 0.5(product of 2 legs).

OpenStudy (anonymous):

thats how i do it??

OpenStudy (anonymous):

wait wait let me do it

OpenStudy (anonymous):

168??

hartnn (hartnn):

168 what? other leg or area?

OpenStudy (anonymous):

area? lol

OpenStudy (anonymous):

i did this.... 21x16=336 (1/2) = 168?

hartnn (hartnn):

no! see my first comment. can u calculate the other leg using pythagoras theorem, just as we did in last problem ? first calculate the other leg.........

OpenStudy (anonymous):

im confused :( lol so i have to do a^2+b^2=c^2?

hartnn (hartnn):

yes! because its a right triangle....

OpenStudy (anonymous):

ok so its gonna be 16^+21^2=c^?

OpenStudy (anonymous):

no wait its 1

hartnn (hartnn):

no.... c is the hypotenuse = 21 \(16^2+b^2=21^2\)

OpenStudy (anonymous):

16^2+b^2=21^2 right?

OpenStudy (anonymous):

yes yes lol got it, wait let me try to solve it lol

OpenStudy (anonymous):

13.60!!

OpenStudy (anonymous):

so no i multiply that with 16 right?

OpenStudy (anonymous):

*now

OpenStudy (anonymous):

then by 0.5

hartnn (hartnn):

yes, thats other leg, now area = 0.5 * 16 * 13.6

hartnn (hartnn):

yup

OpenStudy (anonymous):

is it 108.8?

hartnn (hartnn):

yup, u got it :)

OpenStudy (anonymous):

yay~~

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