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What is wrong with solving the equation x2=3x by dividing both sides of the equation by x? Explain the correct method for solving this equation.
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because you are not allowed to divide by 0 if \(x=0\) you have a solution because you would get \(0=0\)
correct method is to think "if twice a number is the same as three times a number, that number better be 0"
well actually correct method would be two write \[x^2-2x=0\] \[x(x-2)=0\] etc
THANKS SATELLITE GREAT REACTION TIME
ignore my second answer i read it incorrectly i thought it said \(2x=3x\) but actually it was \(x^2=3x\) so all is wrong
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let me start again and do it right
\[x^2=3x\] \[x^2-3x=0\] \[x(x-3)=0\] \[x=0\] or \[x=3\]
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