Question

how do you find out how many solutions there are for x^2+2x+8

Answer 1

try to solve
or use \(b^2-4ac\) are you allowed complex solutions?

Answer 2

yeah

Answer 3

Fundamental theorem of algebra implies that a polynomial of degree n always has n roots, counting repeated roots. So since it's of degree 2, it has 2 roots.

Answer 4

?

Answer 5

Since it's a second degree polynomial (highest term is a power of 2, the x^2), it automatically must have 2 solutions.

Answer 6

oh ok

Answer 7

the maximum no. of solutions is 2.............

Answer 8

It has 2 solutions,
\[ x=-1±i\sqrt{7}. \]

Answer 9

it has no real solution........

Answer 10

thankx