uhh, i dont know any other way to put this up here, to find to the value of x and y: 5x-4y=3y-x+8
that's 1 equation and 2 unknowns.. not enough info
hey let me post a pic of it for u you will better understand i hope! :D
that might help
here yer go!! this problem is evil .
hm.
x+y=2x-4 5x-4y=3y-x+8
Solve the 2 equations
Important details are important, yes they are. Especially if they are geometry details.
ok im going to bed folks.. can someone help him/her solve the equations?
Sure, I got this. I think.
oooh i got it. omg. i feel smart
x-2x+4=y -x+4=y -7y=-6x+8 7y=6x-8 Plug in: 7(4-x)=6x-8 28-7x=6x-8 36=13x x=13/36
Part two...
-13/36+4=y y=131/36
that doesn't look right to me :/
No? It's late here, where did I mess up? :\
just think because it is a regular octagon all sides are equal so all equations are equal, Choose an equation that contains one variable, solve for it and substitute it into another equation.
But they all have both x and y in them, so you have to make a system of equations like bahrom7893 did.
Remember to change the subject to help you ;)
bahrom said to solve these: x+y=2x-4, y = x - 4 5x-4y=3y-x+8, 5x - 4(x - 4) = 3(x - 4) - x + 8 5x - 4x + 16 = 3x - 12 - x + 8 x + 16 = 2x - 4 x + 20 = 2x 20 = x
So I made stupid algebra mistakes then. Right, makes sense, thank you very kindly! XD
you can still solve for one variable and substitute it into another equation to make that equation only have one variable. Then you can get a numerical value for that variable. You will then have to take this value and plug it into an equation to get the other.
y would = 16
then for the side that's x + y...20 + 16 = 36 and because there's 8 sides...36 x 8 = 288
so 288 would be the perimeter....
thanks so much guys! you all make so sexy to be learning!!
lol
Learning is always sexy.
sexy to be living in USA
anyway once again thanks, its 2am, shuteye is needed
Good night and good luck.
good nite, have sexy dreams....
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