how do i solve for x in the following, 7x-5+2x=3-4x+12
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OpenStudy (anonymous):
move all the x terms to one side .. to the left side for example
you do this by adding 4x to both sides of the equation
what will you get ?
OpenStudy (anonymous):
9x-5=-4x+15?
OpenStudy (anonymous):
no
7x-5+2x=3-4x+12 adding 4x to both sides ->
7x +2x+4x -5 = 3+12-4x+4x
13x-5=15
OpenStudy (anonymous):
all the terms of x.
9x+4x=20
OpenStudy (anonymous):
13x=20
x=20/13
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OpenStudy (anonymous):
nok thank you. i had that all messed up
OpenStudy (anonymous):
now we need to move this '5' to the right side since we want all the x terms at the left sides
.. we do this by adding 5 to both sides of the equation
what we get?
OpenStudy (anonymous):
@miteshchvm we better let people try and learn then solve for them ..
OpenStudy (anonymous):
than*
OpenStudy (anonymous):
ya dude @Coolsector ;) sure
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OpenStudy (jiteshmeghwal9):
take the variables at one side & constants at one side as\[7x+2x+4x=3+12+5 .........(By \space Transposition )\]\[13x=20\]by dividing 13 both sides.we have\[\frac{13x}{13}=\frac{20}{13} \implies x=\frac{20}{13}\]