Question

a_(n)−9 a_(n)−1 +26a_(n−2)+24a_(n-3)=0 for n≥3

solve recurrence relation

Answer 1

set up ur characterestic equation\[\lambda^3-9\lambda^2+26\lambda+24=0\]

Answer 2

im stuck :)

Answer 3

maybe equation is not right..??? @bhavin5704 plz recheck

Answer 4

now its ok

Answer 5

what u mean is \[a_{n}−9a_{n−1}+26a_{n−2}+24a_{n-3}=0\]right?

Answer 6

yes

Answer 7

that is